The cube root of 27 is 3. 27 is a perfect cube (3^3 = 27), so its cube root is the exact integer 3. This page shows the exact value, simplified radical form, decimal to 20 decimal places, step-by-step working, and a 3D cube visualisation....
CUBE ROOT OF 27
3
Exact — 27 is a perfect cube (3³ = 27)
Exact form
3
Decimal (6dp)
3.000000
Decimal (10dp)
3.0000000000
Is perfect cube?
Yes ✓
(∛27)³
27 ✓
Between
3 (exact)
STEP-BY-STEP
Find a number k such that k³ = 27
3 × 3 × 3 = 27 ✓
∛27 = 3 (exact)
FUN FACT
cbrt(27) = 3 exactly. 27 = 3^3 is a perfect cube. Among 1 to 30, only 1, 8, and 27 are perfect cubes.
CUBE WITH VOLUME = 27
NEARBY PERFECT CUBES
CUBE ROOT LAWS
27 is a perfect cube: 3^3 = 27. Perfect cubes always have exact integer cube roots.
Verify: 3 x 3 x 3 = 27. The cube root of 27 is exactly 3.
Memorise the perfect cubes: 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000. These have exact integer cube roots.
Check: (cbrt(27))^3 = 27 confirms the answer.
cbrt(27): perfect cube, 3 x 3 x 3 = 27. cbrt(27) = 3 (exact).
Bold bordered = perfect cubes (∛1=1, ∛8=2, ∛27=3)
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Last updated: April 28, 2026 · Verified by EagleCalculator team · Eagle-eyed accuracy for every calculation.