The 10th Fibonacci Number

The 10th Fibonacci number is 55. Index 10 is a milestone term, and the first whose value is a multiple of 5. Every fifth Fibonacci number is divisible by 5, which is the simplest case of the divisibility rule the sequence obeys. It follows from the rule the whole sequence runs on: add the two terms ...

BY POSITION

WORTH TRYING

F(10)

55

RATIO TO F(9)

1.617647

2 digits · previous 34 · next 89 · φ is 1.618034, so this is off by 3.9e-4

Digits

2

Lucas L(n)

123

Sum of F(1)…F(n)

143

Ratio to previous

1.617647059

Exact in a double?

yes

Index n

10

AROUND F(10)

n

F(n)

DIGITS

7

13

2

8

21

2

9

34

2

10

55

2

11

89

2

12

144

3

13

233

3

STEPS

1

Every term is the sum of the two before it, starting from F(0) = 0 and F(1) = 1

2

F(10) = F(9) + F(8) = 34 + 21

3

2 digits, small enough to hold exactly in ordinary arithmetic

4

F(10) = 55

GOLDEN SPIRAL

SQUARE 1 OF 10 — SIDE 1RECTANGLE 1 × 1each square’s side is the next Fibonacci numberthe rectangle is always F(k) × F(k+1)

The squares build the sequence. Each new square takes the whole long side of what is already there, so its side is the sum of the two before it — which is the Fibonacci rule stated in geometry rather than arithmetic. The rectangle is always F(k) by F(k+1), and the quarter arcs join end to end into the spiral. It approaches the golden spiral without ever being one: this is built from circular arcs, and the true golden spiral is a smooth logarithmic curve. Square 10 is picked out in gold.

THE RATIO CLOSING ON φ

n = 3
2.00000000
n = 5
1.66666667
n = 8
1.61538462
n = 12
1.61797753
n = 20
1.61803396
n = 40
1.61803399

Bar length is the distance from φ = 1.618033989, so shorter is closer. The ratio alternates above and below it and the error falls by roughly a factor of φ² each step, which is why n = 40 already matches φ to the last digit a double can hold.

Exact, not floating point. F(78) is the last term that fits exactly in ordinary double arithmetic; F(79) is 14,472,334,024,676,221, which is past the limit. Everything here is computed with exact big integers, so F(500) is right to the final digit rather than rounded. Indices run to 1,000.

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HOW TO USE

  1. 1

    The answer is already here: F(10) = 55. This page opens with index 10 loaded, so nothing needs typing.

  2. 2

    The STEPS panel shows where it comes from: F(9) + F(8) = 34 + 21 = 55.

  3. 3

    The six tiles carry the derived quantities — digit count, the Lucas number, the running total, the ratio to the previous term, and whether the value still fits exactly in ordinary computer arithmetic.

  4. 4

    Change the index to carry on, or switch to IS IT ONE? to test whether some other number appears in the sequence at all.

THE FORMULAS

The ruleF(n) = F(n−1) + F(n−2)
The seedsF(0) = 0, F(1) = 1
Golden ratioφ = (1 + √5) ÷ 2
Binet's formulaF(n) = (φⁿ − ψⁿ) ÷ √5
Ratio limitF(n) ÷ F(n−1) → φ
Sum of the first nF(1) + … + F(n) = F(n+2) − 1
Sum of squaresF(1)² + … + F(n)² = F(n)·F(n+1)
Cassini identityF(n)² − F(n−1)F(n+1) = (−1)ⁿ⁻¹
Greatest common divisorgcd(F(m), F(n)) = F(gcd(m,n))
Lucas numbersL(n) = F(n−1) + F(n+1)
Fibonacci test5N² ± 4 is a perfect square
Zeckendorfa unique sum of non-consecutive terms

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Last updated: July 29, 2026 · Formula verified · Exact big-integer arithmetic, so terms past F(78) are right to the final digit · Eagle-eyed accuracy for every calculation.